So to work out the amount of addressable memory, we must multiply the number of addresses by their size.
Q. Is data word and width of system bus the same?
Data bus. The amount of data that can be carried by the data bus depends on the word size. Word size describes the width of the data bus. At the moment new processors will usually have a word size of 8 bytes (64 bits), allowing for 64 bits to be transferred during each cycle.
Q. What is the same as bus width?
Bus width refers to the number of bits that can be sent to the CPU simultaneously, and bus speed refers to the number of times a group of bits can be sent each second. Latency refers to the number of clock cycles needed to read a bit of information.
- Total Addressable Memory = (2^address bus width) * Data bus width.
- IE a machine with a 16 bit Data Bus and 32 bit address bus would have.
- (2^32)*16 bits of accessible storage.
- or 8GB – Do the math yourself to prove it.
Q. What is the size of data bus in 8086?
Buses and operation All internal registers, as well as internal and external data buses, are 16 bits wide, which firmly established the “16-bit microprocessor” identity of the 8086. A 20-bit external address bus provides a 1 MB physical address space (220 = 1,048,576).
Q. What is size of data bus and address bus in 8086?
All internal registers, as well as internal and external data buses, are 16 bits wide, which firmly established the “16-bit microprocessor” identity of the 8086. A 20-bit external address bus provides a 1 MB physical address space (220 = 1,048,576).
Q. What is data and address bus?
The main difference between address bus and data bus is that the address bus helps to transfer memory addresses while the data bus helps to send and receive data. That is, the address bus is used to specify a physical address in the memory while the data bus is used to transmit data among components in both directions.
