Area is calculated by multiplying the length of a shape by its width. In this case, we could work out the area of this rectangle even if it wasn’t on squared paper, just by working out 5cm x 5cm = 25cm² (the shape is not drawn to scale).

Surface Area Formulas:

1. Volume = (1/3)πr2h.
2. Lateral Surface Area = πrs = πr√(r2 + h2)
3. Base Surface Area = πr2
4. Total Surface Area. = L + B = πrs + πr2 = πr(s + r) = πr(r + √(r2 + h2))

Tricks to solve Volume and Surface Area Problems

1. CUBOID. Let length = l, breadth = b and height = h units.
2. CUBE. Let each edge of a cube be of length a.
3. CYLINDER. Let radius of base = r and Height (or length) = h.
4. CONE. Let radius of base = r and Height = h.
5. SPHERE. Let the radius of the sphere be r.
6. HEMISPHERE.

Surface area and volume are calculated for any three-dimensional geometrical shape. The surface area of any given object is the area or region occupied by the surface of the object. Whereas volume is the amount of space available in an object.

To find the volume of a rectangular object, measure the length, width and height. Multiply the length times the width and multiply the result by the height. The result is the volume. Give the result in cubic units, such as cubic centimeters.

Different Ways to Find Volume

1. Solve for Volume by Space. All physical objects occupy space, and you can find the volume for some of them by measuring their physical dimensions.
2. Solve for Volume by Density and Mass. Density is defined as an object’s mass per a given unit of volume.
3. Solve for Volume by Displacement.

The volume of displaced fluid is equivalent to the volume of an object fully immersed in a fluid or to that fraction of the volume below the surface for an object partially submerged in a liquid. The weight of the displaced portion of the fluid is equivalent to the magnitude of the buoyant force.

The mass of the displaced fluid can be expressed in terms of the density and its volume, m = ρV. The fluid displaced has a weight W = mg, where g is acceleration due to gravity. Therefore, the weight of the displaced fluid can be expressed as W = ρVg.

The aparent weight is a property of objects that corresponds to how heavy the object is. It can be negative if force of buoyancy becomes more than weight when placed in a fluid. We have to apply some external force to balance. Answer verified by Toppr.

When a body of mass m is placed on a weighing machine which is placed in a lift, then actual weight of the body is mg. This reaction exerted by the surface of contact on the body is the apparent weight of the body.

When an object is immersed in a fluid, the object experiences buoyant force in upward direction and weight of object in downward direction. So, the apparent weight of the floating block is equal to zero because the weight of the block acting vertically downwards is balanced by buoyant force acting upwards .

According to the principle of flotation, the weight of a floating body is equal to the weight of the liquid displaced by its submerged part. When a body is immersed partly or completely in a liquid it is under the influence of two forces, 1.