Pass an array by value to a function in C/C++ We know that arguments to the function are passed by value in C by default. However, arrays in C cannot be passed by value to a function, and we can modify the contents of the array from within the callee function.

Arrays are not pointers. This will print in this way when you assign a string reference to a pointer you have to use *ptr to print the value of a pointer otherwise in your case print(d) that is like cout< in c++ it will only print the location of the d[0].

How to pass an array by reference in C++ If we pass the address of an array while calling a function, then this is called function call by reference. The function declaration should have a pointer as a parameter to receive the passed address, when we pass an address as an argument.

In order to pass a char array to a function you should do what you are currently doing, that is, pass a pointer to the (first element of the) array. void putAddress(char *, char *, char *, char *); PS: Your next problem is knowing (making putAddress aware of) each array’s length.

Answer: An array can be passed to a function by value by declaring in the called function the array name with square brackets ( [ and ] ) attached to the end. When calling the function, simply pass the address of the array (that is, the array’s name) to the called function.

There are three ways to pass a 2D array to a function:

1. The parameter is a 2D array int array[10][10]; void passFunc(int a[][10]) { // …
2. The parameter is an array containing pointers int *array[10]; for(int i = 0; i < 10; i++) array[i] = new int[10]; void passFunc(int *a[10]) //Array containing pointers { // …

Let’s understand through an example.

1. #include
2. using namespace std;
3. int main()
4. {
5. int ptr1[5]; // integer array declaration.
6. int *ptr2[5]; // integer array of pointer declaration.
7. std::cout << “Enter five numbers :” << std::endl;
8. for(int i=0;i<5;i++)

We declare an int array with 5 ints and assign the array numbers variable to our int pointer, ptr1. The numbers variable holds the address of the first element in the array. Assigning it to ptr1 numbers is treated as an pointer. We then get the value of the first element in the array using array notation.

Update the second variable (pointed by b) by the value of the first variable saved in the temporary variable. In C, we cannot pass an array by value to a function. Whereas, an array name is a pointer (address), so we just pass an array name to a function which means to pass a pointer to the array.

In C, we cannot pass an array by value to a function. Whereas, an array name is a pointer (address), so we just pass an array name to a function which means to pass a pointer to the array. For example, we consider the following program:

But as mentioned in other answers, it’s not that common to do this. Usually a pointer-to-array is passed only when you want to pass a 2d array, where it suddenly looks a lot clearer, as below. A 2D array is actually passed as a pointer to its first row.

The instruction int (*ope [4]) (int, int); defines the array of function pointers. Each array element must have the same parameters and return type. The statement result = ope [choice] (x, y); runs the appropriate function according to the choice made by the user The two entered integers are the arguments passed to the function.