By using magnet, iron nails can be separated from the mixture of iron nails and saw dust.

gravity method

magnet

We can separate the iron filling from the mixture by using magnet , because we know iron filling can easily attracted towards the magnets .

Answer: Use magnet to remove iron filings (magnetic attraction) *Add water to remaining sugar/sand to dissolve sugar (solubility of sugar). *Pour solution through filter to remove sand (solid). *Heat or allow water to evaporate to remove the water – sugar remains (solid).

sawdust is not soluble in water.

Explanation: No. Saw dust does not dissolve in water but very tiny particles of the saw dust may form a colloidal suspension and may alter the colour of the water even after the bigger particles of wood that the saw dust comprises settled down. …

Answer: Sedimentation and decantation cannot be used to separate sawdust from water because sawdust is not heavier than water. Sedimentation and decantation can only be used to separate an insoluble solid from a liquid if the solid is heavier than the liquid.

When chalk powder or sand is added to water, it settles down what do you infer? Chalk doesnot dissolve in water. Chalk comprises CaCO3 which is insoluble in water because the forces of attraction between calcium and carbonate ions are stronger than ions of calcium carbonate and water.

A tiny proportion of the chalk will dissolve and another tiny proportion may react with dissolved carbon dioxide (in the form of carbonic acid). You get a slurry !

On dissolving chalk in water, it does not dissolve completely in water. The chalk powder settles down which can be seen by bare eyes easily. Therefore, chalk powder dissolved in water is an example of a suspension. Note: Solute dissolves completely in a solvent in true solutions.

Explanation: DISSOLVE THE MIXTURE OF SAND AND CHALK POWDER IN WATER AND FILTER THE SOLUTION . THE SAND IS COLLECTED AS A RESIDUE IN THE FILTER PAPER. EVAPORATE THE FILTRATE SO AS TO OBTAIN CHALK POWDER.

Separating Sand and Salt Probably the easiest method to separate the two substances is to dissolve salt in water, pour the liquid away from the sand, and then evaporate the water to recover the salt.

Complete answer: We can separate the mixture of common salt and chalk powder by putting the mixture in water. As we know that common salt is a homogeneous mixture, so it will dissolve with water uniformly and chalk powder is heterogeneous so it could be separated by the filtration method by using filter paper.

Calcium carbonate CaCO3 is the main component in chalk. In water the solubility of calcium carbonate is extremely low therefore an extremely minute amount of CaCO3 is able to dissolve in a normal amount of water.

A colloid is just a mixture where a substance of dispersed insoluble particles is suspended throughout another substance. Chalk powder is very little soluble in water therefore this will form an suspension. Copper sulfate is very soluble in water, thereby making it a solution.

Explanation: Chalk powder mixed with water is a suspension solution and protein dissolved in water is a colloidal solution. Brownian movement is a phenomenon of continuous random motion of colloidal particles. Therefore, beaker B shows Brownian movement.

The correct option is c. on dissolving chalk powder in water , a suspension is obtained. The mixture is stirred for sometime to ensure the uniform dispersion of chalk powder in water. Suspension is a heterogeneous mixture of particles from which the particles settle down with time.

Beaker B: Chalk powder is insoluble in water so it will form a non homogeneous mixture and initially the particle can scatter the beam of light but when the particle will settle down they will not show Tyndall effect.

-The scattering of light by colloidal solution tells us that the colloidal particles are much bigger than the particles of a true solution. – We can see that the correct options are (B) and (D), milk and starch solution are the colloids, hence these will show the tyndall effect.

mixture of water and milk shows Tyndall effect because it becomes colloidal in nature……

Since colloids have particles in them which scatter the passed light, they show Tyndall impact. The sugar solution is a true solution and not a colloid solution. Hence, the Tyndall effect is not shown by the sugar solution.

B. Tyndall effect can be used to distinguish between a colloidal solution and a true solution. It mainly consists of a colloidal suspension of rubber globules in a watery liquid. Latex is a colloidal solution of rubber particles which are negatively charged.

Therefore, tyndall effect will be shown by soap solution above critical micelle concentration. The correct answer is B. Soap solution is colloidal or not depending on kraft temperature and critical micelle concentration.

Common salt solution and copper sulphate solution does not show Tyndall effect as they are less than 1 nm in diameter and cannot be seen by naked eye. Due to its small particle size, they do not scatter a beam of light passing through the solution.

Milk is a colloid that contains globules of fat and protein. When a beam of light is directed at a glass of milk, the light is scattered. This is a great example of the Tyndall effect. When a torch is switched on in a foggy environment, the path of the light becomes visible.

Tyndall effect is due to the scattering of light by colloidal particles. Sugar solution is a true homogeneous solution which will not show Tyndall effect.