Collective ownership of the means of production is the defining characteristic of socialism, where “collective ownership” can refer to society-wide ownership or to cooperative ownership by an organization’s members.

Why do members of food-collecting societies not have private ownership of land? Land has no intrinsic value to foragers, only the animals and plants on the land. members of these societies are lazy and have no interest in work.

Of the following economic activities, which finds the individual ownership of land most important? intensive agriculture. You just studied 30 terms!

• as growing populations expanded further from bountiful wild resources, they domesticated animals and plants in an effort to reproduce former abundance.
• global population growth may have filled most of the world’s habitable regions, forcing people to domesticate plants and animals.

Basically, common ownership is about universally shared use of the same resources. Collective ownership is a subset of common ownership, in that it is diffused (shared by everyone in the collective) but still “private” in the sense of excluding ownership – and use – to those outside of the collective.

Colligative properties are the properties which depend upon the number of solute particles present in the solution. Optical activity does not depends upon number of particles present hence it is not a colligative property. Hence, option B is the answer.

S1: Vapour pressure is a colligative property. S2: Freezing point of a solution is always lower than that of the pure solvent.

Other non-colligative properties include viscosity, surface tension, and solubility.

glucose solution

Remember, the greater the concentration of particles, the lower the freezing point will be. 0.1mCaI2 will have the lowest freezing point, followed by 0.1mNaCl, and the highest of the three solutions will be 0.1mC6H12O6, but all three of them will have a lower freezing point than pure water.

Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams. Value of van’t Hoff factor is least for urea solution, so there will be least depression in freezing point i.e. maximum freezing point.

The lowest van’t hoff factor will result in the least depression in freezing point and hence that solution will have the highest freezing point. Hence, the correct option is D, glucose.

Complete step-by-step answer: Since the cryoscopic constant is the same for all compounds, the compound with higher i x C value will have maximum depression in freezing point. The solution having maximum i x C value and that shows maximum depression in freezing point is Al2(SO4)3 .

Thus the value of i=2 and its effective concentration will be 0.02M . Now, from the above compounds C2H5OH has the least concentration. It means its depression in the freezing point will be minimum which means It will have the highest freezing point. Hence, Option (B) is the correct option.

The freezing point of equimolal soution will be highest for :

• B. Ca(No3)2.
• C. La(NO3)3.
• Solution. La(NO3)3will furnish four ions and thus will develop more lowering in freezing point where as glucose gives only one particle and thus lowering in freezing point is minimum.

Pure water has the maximum freezing point. The addition of non-volatile solute such as NaCl decreases the freezing point of water. So, NaCl solutions will have lower freezing points than pure water.

This implies that dissociation into ions is maximum in the case of D, and thus least vapour pressure is observed.

benzene (C6H6) has a vapour pressure of 395 mm Hg and a 50.50 mixture y mass of benzene and X has a vapour pressure of 299 mm Hg. So.

cacl2

and “1%NaCl in water” gives two ions so it will have highest boiling point.

Branching makes a molecule more compact, which reduces surface area and van der Waals attractions. Ethers generally have higher boiling points than alkanes of comparable molecular weight because both van der Waals forces and dipole-dipole-interactions in an ether must be overcome for the ether to boil.

There is no point of boiling for glucose. It changes into a liquid from crystalline form at the same temperature, 295 *F, as its decomposition point. In other words it can not exist as a stable liquid that can boil.

Bacl2 will have higher boiling point as boiling point is a colligative property . And the van’t hoff factor of nacl is more than bacl2. Consequently, 0.1M bacl2 will have higher boiling point than 0.1M nacl.

The boiling point depends only on the Van’t Hoff factor. That means higher the Van’t Hoff factor, higher will be the boiling point and vice-versa. Hence, 0.1 M of NaCl has the higher boiling point.

0.1M NaCl d. 0.1 M Glucose. FeCl3 solution will have highest boiling point. This is because it is ionic and will have highest number of solute particles which will decrease the vapour pressure and increase the bp of solution.

The boiling points of 0.05 m NaCl and 0.05 m BaCl2 will be different due to different particle concentration in the solution.