Since there are two forces acting on the upper and lower springs, the overall spring system will stretch further than expected. The result is that the spring constants of springs in series add as reciprocals (Equation 1).

k

Stiffness is the extent to which an object resists deformation in response to an applied force. The complementary concept is flexibility or pliability: the more flexible an object is, the less stiff it is.

We define K-effective as “the ratio of the number of neutrons resulting from fission in the current generation to the total number lost by absorption and leakage in the preceding generation.” The ratio of K-effective to K-infinity is therefore: Absorption. Fission. Leakage.

Answer. Hooke’s Law states that the force needed to compress or extend a spring is directly proportional to the distance you stretch it. As an equation, Hooke’s Law can be represented as F = kx, where F is the force we apply, k is the spring constant, and x is the extension of the material (typically in meters).

Hooke’s Law states that the force of a spring is proportional to the extention of the spring. It is an important approximation of real spring (and other elastic bodies) properties. It doesn’t require the mass of the spring to be zero, as it is not dependent on the mass of the spring.

Ideal Spring – a notional spring used in physics—it has no weight, mass, or damping losses. The force exerted by the spring is proportional to the distance the spring is stretched or compressed from its relaxed position.

In general, the spring constant is inversely proportional to the number of coils in the spring, so shorter springs are stiffer springs, all other things being equal. To stretch or compress a spring, a force must be applied to it.

When a mass is hung vertically from a spring, the spring stretches. The force on the mass due to the spring is proportional to the amount the spring is stretched. The restoring force results in the mass eventually returning to the equilibrium position.

If you are thinking of a mass attached to a spring attached to the ceiling, then yes, the mass is proportional to the spring displacement. This follows since in the case of an object being acted on by gravity, a=g, and thus |Δs|=mg/k.

Elastic potential energy