First, put the equation of the line given into slope-intercept form by solving for y. You get y = -2x +5, so the slope is –2. Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6.

What is the equation of the line that is perpendicular to the given line and passes through the point (3, 4)? y = –1/3x + 5. y = –1/3x + 3.

Find the Equation of a Line Given That You Know a Point on the Line And Its Slope. The equation of a line is typically written as y=mx+b where m is the slope and b is the y-intercept. If you a point that a line passes through, and its slope, this page will show you how to find the equation of the line.

Once you know the slope of the line, plug it in for m in y = mx + b. For example, if you used the formula and found that the slope is 2, you would write y = 2x + b. The example below shows the first steps you would take if you needed to write an equation of the line through the points (2,5) and (4,13).

In the equation y = mx + c the value of m is called the slope, (or gradient), of the line. It can be positive, negative or zero. The value of c is called the vertical intercept of the line. It is the value of y when x = 0. When drawing a line, c gives the position where the line cuts the vertical axis.

The equation of any straight line, called a linear equation, can be written as: y = mx + b, where m is the slope of the line and b is the y-intercept. The y-intercept of this line is the value of y at the point where the line crosses the y axis.

Slope-intercept form, y=mx+b, of linear equations, emphasizes the slope and the y-intercept of the line.