For this particular equation, b=1, but for a line with slope -4 that goes through the point (1,2), the y-intercept changes. Now solve for b to get b=6. Your equation is now: y= -4x+6 or 4x+y-6=0.

1 Answer. The point-slope equation of the line that passes through the point (2,1) and has the slope 5 , is y−1=5(x−2) . The generic equation for point-slope form is y−y1=m(x−x1) , where m is the slope and x1 and y1 are the given point.

The equation of a line is typically written as y=mx+b where m is the slope and b is the y-intercept. If you a point that a line passes through, and its slope, this page will show you how to find the equation of the line.

We have the point ( -4 , 2 ) so x1 = -4 and y1 = 2. The slope is still 1/2 so m = 1/2. y = 1/2 x +4 Final answer!

Answer: y = 7 is the equation of the line that passes through the point ( -2, 7 ) and has a slope of zero.

In the formula y=mx + b, m is the slope and b is the y intercept. We need the slope and y intercept numbers to write the equation.

1 Expert Answer The general formula for the equation of a line in slope – intercept form is y = mx + b. You will likely need to memorize this formula. The m represents the slope of the line, and the b represents the y coordinate of the y – intercept of the line. If the slope is 2/3, plug in 2/3 for m.

Start with the general point-slope formula y – k = m(x – h), where (h, k) is the given point and m is the given slope. Given the point (4, -1), we substitute 4 for h in this general formula, -1 for k and 2/3 for m: y + 1 = (2/3)(x – 4) is the desired formula.

1 Expert Answer If a line has a slope of 2/3, then the slope intercept form equation of that line will be: y = 2/3 x + b where b is the y-intercept.

y=mx+b is the slope-intercept form of a line. m is the slope and b is the y intercept. So to write an equation of a line with a slope of 2/3 and y-intercept of 7, you would just plug in that slope, 2/3 for m and the y-intercept, 7 for b. So y=mx+b becomes y=2/3x+7.

y = mx + c . Since, it passes through the point (2, 3) & has y-intercept of 5 units , therefore, we must have; 3 = 2m + 5 ==> m = -1 .

Y=mX+b WHERE m=SLOPE & b=Y INTERCEPT. Y=2X-5 IS THE EQUATION.

Which equation represents a line having a slope 5/2 and y-intercept (0, -4)? y = -4x + 5/2.

Using the slope-intercept form, the slope is 13 .

Algebra Examples Using the slope-intercept form, the slope is −2 .

Using the slope-intercept form, the y-intercept is 0 .

Explanation: The slope-intercept form is y=mx+b where m is the slope value. In the equation y=2x , the m value is 2 . Therefore, 2 is the slope.

Using the slope-intercept form, the slope is −2 .

Therefore: The slope is: m=2. The y -intercept is: b=0 or (0,0)

Using the slope-intercept form, the slope is 2 .

Using the slope-intercept form, the y-intercept is 7 .

The slope of a line characterizes the direction of a line. To find the slope, you divide the difference of the y-coordinates of 2 points on a line by the difference of the x-coordinates of those same 2 points.

Explanation: Since there is no x then the line is horizontal and has a slope of 0. Go to 4 on the y-axis and just draw a horizontal line that runs both through the negative and positive sides. Desmos. Every point has a 4 for its y coordinate.

We can see that our given equation is slope-intercept form of equation , where, m = Slope of line, b = The y-intercept or initial value. So, the graph for our given equation will have a slope of 2 and it will y-axis at y=-4.

As long as y never changes value, it is always c, then you have a solution. In that case, you will end up with a horizontal line. Example 3: Graph the linear equation y = 4. It looks like it fits the form y = c….

Explanation: y=2x−3 is in slope intercept form for a linear equation, y=mx+b , where m is the slope and b is the y-intercept. The y-intercept is the point at which x=0 and y=−3 , which is point (0,−3) You can plot this point on your graph. The slope is can be described as riserun , and can be written as 21 .

No. All linear functions can be written in the form y = mx + b, where m is the slope and b is the y-intercept (slope-intercept form). This function, y = 5/x, is a hyperbola, with a vertical asymptote at x = 0 and horizontal asymptote at y = 0.

An equation for a straight line is called a linear equation. The general representation of the straight-line equation is y=mx+b, where m is the slope of the line and b is the y-intercept.