The time between two identical points on a sine wave is called the period, and at a frequency of 60Hz (60 cycles per second) there will be a period of approximately 16.6 milliseconds, as shown in the diagram.

0.02 s

The period of a 50 kHz sine wave is 2 x 10-5 second.

In the example above, f = 1/10 ms, or 100 Hz (100 cycles in one second).

Answer: Period of the given wave is 0.5 milliseconds.

The wave speed, v, is how fast the wave travels and is determined by the properties of the medium in which the wave is moving. If the medium is uniform (does not change) then the wave speed will be constant. The speed of sound in dry air at 20 C is 344 m/s but this speed can change if the temperature changes.

Time Period: It is the time taken by a body to complete one oscillation. Hence, the Frequency and Time period are calculated as follows. Time period = Time taken by the pendulum/Number of oscillations made by the pendulum. Hence, the Time period and frequency are 2 seconds and 0.5 Hertz respectively.

How to analyze a pendulum in swing

1. Determine the length of the pendulum.
2. Decide a value for the acceleration of gravity.
3. Calculate the period of oscillations according to the formula above: T = 2π√(L/g) = 2π * √(2/9.80665) = 2.837 s .
4. Find the frequency as the reciprocal of the period: f = 1/T = 0.352 Hz .

In the SHM of the mass and spring system, there are no dissipative forces, so the total energy is the sum of the potential energy and kinetic energy. As the object starts to move, the elastic potential energy is converted into kinetic energy, becoming entirely kinetic energy at the equilibrium position.

The total energy (E) of an oscillating particle is equal to the sum of its kinetic energy and potential energy if conservative force acts on it. The velocity of a particle executing SHM at a position where its displacement is y from its mean position is v = ω√a2 – y2.